2x^2+60x+70=0

Solution for 2x^2+60x+70=0 equation:

2x^2+60x+70=0

a = 2; b = 60; c = +70;
Δ = b2-4ac
Δ = 602-4·2·70
Δ = 3040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3040}=\sqrt{16*190}=\sqrt{16}*\sqrt{190}=4\sqrt{190}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{190}}{2*2}=\frac{-60-4\sqrt{190}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{190}}{2*2}=\frac{-60+4\sqrt{190}}{4}
$